(10/x)+(6/x^2)=0

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Solution for (10/x)+(6/x^2)=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

10/x+6/(x^2) = 0

10*x^-1+6*x^-2 = 0

t_1 = x^-1

6*t_1^2+10*t_1^1 = 0

6*t_1^2+10*t_1 = 0

DELTA = 10^2-(0*4*6)

DELTA = 100

DELTA > 0

t_1 = (100^(1/2)-10)/(2*6) or t_1 = (-100^(1/2)-10)/(2*6)

t_1 = 0 or t_1 = -5/3

t_1 = -5/3

x^-1+5/3 = 0

1*x^-1 = -5/3 // : 1

x^-1 = -5/3

-1 < 0

1/(x^1) = -5/3 // * x^1

1 = -5/3*x^1 // : -5/3

-3/5 = x^1

x = -3/5

t_1 = 0

x^-1+0 = 0

x^-1 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x = -3/5

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